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Surface Tension — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsSurface Tension1 Mark
MCQ
Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and $50 \mathrm{dyne} / \mathrm{cm}$ respectively Ratio of heights of liquids in the two tubes $\frac{h_1}{h_2}$ is
  • A
    $\frac{10}{9}$
  • B
    $\frac{3}{10}$
  • C
    $\frac{10}{3}$
  • ✓
    $\frac{9}{10}$
✓

Answer

Correct option: D.
$\frac{9}{10}$
(d) Ascent formula $h=\frac{2 T \cos \theta}{r d g}$
$ \Rightarrow \frac{h_1}{h_2}=\frac{T_1}{T_2} \times \frac{d_2}{d_1} \quad(r, \theta \text { and } g \text { are constants })$
$ =\frac{60}{50} \times \frac{0.6}{0.8}=\frac{9}{10}$

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