Two capillary tubes of same radius $r$ but of lengths $l_1$ and $l_2$ are fitted in parallel to the bottom of a vessel. The pressure head is $P$. What should be the length of a single tube that can replace the two tubes so that the rate of flow is same as before
  • A${l_1} + {l_2}$
  • B$\frac{1}{{{l_1}}} + \frac{1}{{{l_2}}}$
  • C$\frac{{{l_1}{l_2}}}{{{l_1} + {l_2}}}$
  • D$\frac{1}{{{l_1} + {l_2}}}$
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