A tank $5\, m$ high is half-filled with water and then is filled to the top with oil of density $0.85\, g/cm^3$. The pressure at the bottom of the tank, due to these liquids is ....... $g\, dyne/cm^2$
Medium
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Pressure at the bottom $\mathrm{P}=\left(\mathrm{h}_{1} \mathrm{d}_{1}+\mathrm{h}_{2} \mathrm{d}_{2}\right) \frac{\mathrm{g}}{\mathrm{cm}^{2}}$
$=[250 \times 1+250 \times 0.85]=250[1.85] g$
$=462.5 \mathrm{g}$ $dyne/cm ^{2}$
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