MCQ
Two charged capacitors have their outer plates fixed and inner plates connected by a spring of force constant ' $k$ '. The charge on each capacitor is q. Find the extension in the spring at equilibrium
  • $\frac{q^2}{2 A \varepsilon_0 k}$
  • B
    $\frac{q^2}{4 A \varepsilon_0 k}$
  • C
    $\frac{q^2}{A \varepsilon_0 k}$
  • D
    $0$

Answer

Correct option: A.
$\frac{q^2}{2 A \varepsilon_0 k}$
a
(a)

$F=k x=\frac{q^2}{2 A \varepsilon_0}$

$x=\frac{q^2}{2 A \varepsilon_0 k}$

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