Two coils have a mutual inductance 0.005 ,H. The current changes … - Vidyadip

MCQ

Two coils have a mutual inductance $0.005 \,H$. The current changes in the first coil according to equation $I = {I_0}\sin \omega \,t$, where ${I_0} = 10\,A$ and $\omega =100\pi\; radian/sec$. The maximum value of $e.m.f$. in the second coil is

A
$2\, \pi$
✓
$5\, \pi$
C
$\pi$
D
$4\, \pi$

✓

Answer

Correct option: B.

$5\, \pi$

b
(b)$e = M\frac{{di}}{{dt}} = 0.005 \times \frac{d}{{dt}}({i_0}\sin \omega t)$ $ = 0.005 \times {i_0}\omega \cos \omega \,t$

$\therefore {e_{\max }} = 0.005 \times 10 \times 100\pi = 5\pi $

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