Two coils have a mutual inductance 0.005 H. The current changes i… - Vidyadip

MCQ

Two coils have a mutual inductance $0.005 H$. The current changes in the first coil according to equation $I=I_0 \sin \omega t$, where $I_0=10 \mathrm{~A}$ and $\omega=100\ \pi\ \mathrm{radian} / \mathrm{sec}$. The maximum value of e.m.f. in the second coil is

A
$2 \pi$
✓
$5 \pi$
C
$\pi$
D
$4 \pi$

✓

Answer

Correct option: B.

$5 \pi$

$e=M \frac{d i}{d t}=0.005 \times \frac{d}{d t}\left(i_0 \sin \omega t\right)=0.005 \times i_0 \omega \cos \omega t $
$ \therefore e_{\max }=0.005 \times 10 \times 100 \pi=5 \pi$

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