MCQ
Two conducting circular loops $A $and $B$ are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them $1$s:
  • $\frac{\mu_0 \pi a^2}{2 b}$
  • B
    $\frac{\mu_0}{2 \pi} \cdot \frac{b^2}{a}$
  • C
    $\frac{\mu_0 \pi b^2}{2 a}$
  • D
    $\frac{\mu_0}{2 \pi} \cdot \frac{a^2}{b}$

Answer

Correct option: A.
$\frac{\mu_0 \pi a^2}{2 b}$
a
$\phi=\mathrm{Mi}=\mathrm{BA}$

$\Rightarrow \mathrm{Mi}=\frac{\mu_0 \mathrm{i}}{2 \mathrm{~b}} \pi \mathrm{a}^2$

$\therefore \mathrm{M}=\frac{\mu_0 \pi \mathrm{a}^2}{2 \mathrm{~b}}$

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