Question
Two cubes each of volume $27cm^3$ are joined end to end to form a solid. Find the surface area of the resulting cuboid.
✓
Answer
Let the length of each side of each cube $=5 cm$.
Now,
Volume of each cuboid $=27 cm^3$
$\Rightarrow s^3=27$
$\Rightarrow s=3 cm$
When two cubes of each side, 3 cm is joined end to end, then a cuboid is formed.
Now, length of cubiod $( l )=6 cm$,
breadth of cubiod (b) $=3 cm$ and
height of cubiod (h) $=3 cm$
$\therefore \text { Total surface area }=(lb+bh+lh)$
$=2[(6 \times 3)+(3 \times 3)(3 \times 6)]$
$=2[18+9+18]$
$=2 \times 45$
$=90 cm^2$
Now,
Volume of each cuboid $=27 cm^3$
$\Rightarrow s^3=27$
$\Rightarrow s=3 cm$
When two cubes of each side, 3 cm is joined end to end, then a cuboid is formed.
Now, length of cubiod $( l )=6 cm$,
breadth of cubiod (b) $=3 cm$ and
height of cubiod (h) $=3 cm$
$\therefore \text { Total surface area }=(lb+bh+lh)$
$=2[(6 \times 3)+(3 \times 3)(3 \times 6)]$
$=2[18+9+18]$
$=2 \times 45$
$=90 cm^2$
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