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STD 11 - 13. oscillations — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 13. oscillations4 Marks
MCQ
Two damped spring-mass oscillating systems have identical spring constants and decay times. However, system $A's$ mass $m_A$ is twice system $B's$ mass $m_B$ . How do their damping constants, $b$ , compare ?
  • A
    $b_A = 4b_B$
  • B
    $b_A = 2b_B$
  • C
    $b_A = b_B$
  • ✓
    ${b_A} = \frac{1}{2}{b_B}$
✓

Answer

Correct option: D.
${b_A} = \frac{1}{2}{b_B}$
d
Damping coefficient $=2 \sqrt{\mathrm{km}}$

$=2 \mathrm{m} \omega$

$\alpha \mathrm{m}$

$\mathrm{m}_{\mathrm{A}}=\mathrm{m}$     $\mathrm{m}_{\mathrm{B}}=\frac{\mathrm{m}}{2}$

$\frac{b_{A}}{b_{B}}=\frac{1}{2}$

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