MCQ
Two dice are rolled simultaneously. The probability that they show different faces is :
- A$\frac{2}{3}$
- B$\frac{1}{6}$
- C$\frac{1}{3}$
- ✓$\frac{5}{6}$
✓
Answer
Correct option: D.
$\frac{5}{6}$
Two dice are rolled simultaneously
$\therefore$ No. of total events $=6^2=36$
$\therefore$ No. of different face can be
$=36 - ($same faces$)$
Same face are $(1,1),(2,2),(3,3),(4,4),(5,5)$ and $(6,6)=6$
$\therefore 36-6=30$
$\therefore\ \text{Probability P (E)}=\frac{\text{m}}{\text{n}}=\frac{30}{36}=\frac{5}{6}$
$\therefore$ No. of total events $=6^2=36$
$\therefore$ No. of different face can be
$=36 - ($same faces$)$
Same face are $(1,1),(2,2),(3,3),(4,4),(5,5)$ and $(6,6)=6$
$\therefore 36-6=30$
$\therefore\ \text{Probability P (E)}=\frac{\text{m}}{\text{n}}=\frac{30}{36}=\frac{5}{6}$
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