MCQ
Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on first dice and a multiple of 3 on the second dice.
  • A
    $\frac{4}{6}$
  • B
    $\frac{2}{6}$
  • $\frac{1}{6}$
  • D
    $\frac{1}{36}$

Answer

Correct option: C.
$\frac{1}{6}$
Total cases = 6 × 6
Let A be the event of getting a multiple of 2 on first dice and a multiple of 3 on the second dice.
Hence, A = {(2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6)} n(A) = 66
$∴\text{P(A)}=\frac{6}{36}=\frac{1}{6}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free