MCQ
Two dice are thrown simultaneously. Find the probability of getting an even number as the sum.
- A$\frac{1}{6}$
- B$\frac{1}{2}$
- C$\frac{5}{6}$
- D$\frac{1}{3}$
Two dice are thrown simultaneously. Find the probability of getting an even number as the sum.
Solution:
Total number of possible cases = 36
Favourable cases of getting even number as the sum
= {(1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6), (5,1), (5, 3), (5, 5), (6, 2), (6, 4), (6, 6)}
Total number of favourable cases = 18
P(getting even number as the sum)
$=\frac{18}{36}=\frac{1}{2}$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Given 5 different green dyes, four different blue dyes and three different red dyes, the number of combinations of dyes which can be chosen taking at least one green and one blue dye is.
[Hint: Possible numbers of choosing or not choosing 5 green dyes, 4 blue dyes and 3 red dyes are 25 , 24 and 23 , respectively.]