MCQ
Two different coins are tossed simultaneously. The probability of getting at least one head is :
- A$\frac{1}{4}$
- B$\frac{1}{8}$
- ✓$\frac{3}{4}$
- D$\frac{7}{8}$
✓
Answer
Correct option: C.
$\frac{3}{4}$
When two different coins are tossed simultaneously, then total possibilities $= 4,$
i.e. $\text{\{(H, H), (H, T), (T, H), (T, T)\}}$
Number of favourable outcomes for at least one head $= 3,$
i.e. $\text{\{(H, T), (T, H), (T, H).\}}$
$\therefore$ Probability of getting at least one nead $=\frac{3}{4}$
i.e. $\text{\{(H, H), (H, T), (T, H), (T, T)\}}$
Number of favourable outcomes for at least one head $= 3,$
i.e. $\text{\{(H, T), (T, H), (T, H).\}}$
$\therefore$ Probability of getting at least one nead $=\frac{3}{4}$
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