- AThe final temperature is greater for the isothermal process
- BThe final pressure is greater for the isothermal process
- CThe work done by the gas is greater for the isothermal process
- ✓All of the above
For isothermal process: $T_{2}=T_{o}$
For adibatic process: $T_{o}\left(V_{o}\right)^{\gamma-1}=T(V)^{\gamma-1}$
As $V>V_{o} \Longrightarrow T Thus final temp. is greater for isothermal process. For isothermal process: $P_{o} V_{o}=P_{i} V \quad \Longrightarrow P_{i}=P_{o} \frac{V_{o}}{V}$ For adibatic process: $P_{o}\left(V_{o}\right)^{\gamma}=P_{a}(V)^{\gamma}$ $\Longrightarrow P_{a}=P_{o}\left(\frac{V_{o}}{V}\right)^{\gamma}$ As $\gamma>1 \quad$ (always) $\Longrightarrow P_{i}>P_{a}$
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$(i)$ The source may be moving towards the observer with a velocity of $30\,ms^{-1}$
$(ii)$ The source may be moving towards the observer with a velocity of $33\,ms^{-1}$
$(iii)$ The observer may be moving towards the source with a velocity of $30\,ms^{-1}$
$(iv)$ The observer may be moving towards the source with a velocity of $33\,ms^{-1}$
