MCQ
Two gases have the same initial pressure, volume and temperatue. They expand to the same final volume, one adiabatically and the other isothermally
  • A
    The final temperature is greater for the isothermal process
  • B
    The final pressure is greater for the isothermal process
  • C
    The work done by the gas is greater for the isothermal process
  • All of the above 

Answer

Correct option: D.
All of the above 
d
Work done is equal to area under the P-V graph, thus work done by gas is greater for isothermal process.

For isothermal process: $T_{2}=T_{o}$

For adibatic process: $T_{o}\left(V_{o}\right)^{\gamma-1}=T(V)^{\gamma-1}$

As $V>V_{o} \Longrightarrow T

Thus final temp. is greater for isothermal process.

For isothermal process: $P_{o} V_{o}=P_{i} V \quad \Longrightarrow P_{i}=P_{o} \frac{V_{o}}{V}$

For adibatic process: $P_{o}\left(V_{o}\right)^{\gamma}=P_{a}(V)^{\gamma}$

$\Longrightarrow P_{a}=P_{o}\left(\frac{V_{o}}{V}\right)^{\gamma}$

As $\gamma>1 \quad$ (always) $\Longrightarrow P_{i}>P_{a}$

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