MCQ
Two identical conducting rods are first connected independently to two vessels, one containing water at $100^o C$ and the other containing ice at $0^oC$. In the second case, the rods are joined end to end and connected to the same vessels. Let ${q_1}$ and ${q_2}$ $g / s$ be the rate of melting of ice in two cases respectively. The ratio of ${q_1}/{q_2}$ is
  • A
    $\frac{1}{2}$
  • B
    $\frac{2}{1}$
  • $\frac{4}{1}$
  • D
    $\frac{1}{4}$

Answer

Correct option: C.
$\frac{4}{1}$
c
(c)Initially the rods are placed in vessels as shown below

$\frac{Q}{t} = \frac{{({\theta _1} - {\theta _2})}}{R}$

${\left( {\frac{Q}{t}} \right)_1} = \frac{{mL}}{t} = {q_1}L = \frac{{(100 - 0)}}{{\frac{R}{2}}}$   ... $(i)$

Finally when rods are joined end to end as shown

$\Rightarrow {\left( {\frac{Q}{t}} \right)_2} = \frac{{mL}}{t} = {q_2}L = \frac{{(100 - 0)}}{{2R}}$                   ... $(ii)$

From equation $(i)$ and $(ii)$ ,  $\frac{{{q_1}}}{{{q_2}}} = \frac{4}{1}$

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