MCQ
Two inductors $L_1$ and $L_2$ are connected in parallel and $a$ time varying current flow  as shown the Ratio of currents $i_1/i_2$ at any time $t$ is
  • A
    $L_1/ L_2$
  • $L_2 / L_1$
  • C
    $\frac{L^2_1}{(L_1 + L_2)^2}$
  • D
    $\frac{L^2_2}{(L_1 + L_2)^2}$

Answer

Correct option: B.
$L_2 / L_1$
b
since $L_{1}$ and $L_{2}$ are connected in parallel. Potential difference across $L_{1}$ is equal to

that across $L_{2}$ i.e. $\mathcal{E}_{1}=\mathcal{E}_{2}$

Or $-L_{1} \frac{d i_{1}}{d t}=-L_{2} \frac{d I_{2}}{d t}$

Or $L_{1} \int d i_{1}=L_{2} \int d i_{2}$

Or $L_{2} i_{2}=L_{1} i_{1}$

or $\frac{i_{1}}{i_{2}}=\frac{L_{2}}{L_{1}}$

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