CBSE BoardEnglish MediumSTD 10MathsQuadratic Equations5 Marks
Question
Two number differ by 4 and their product is 192. Find the numbers.
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Answer
Let first number = x
Then second number = x - 4
According to the condition,
$\Rightarrow x(x - 4) = 192$
$\Rightarrow x^2 - 4x - 192 = 0$
$\Rightarrow x^2 - 16x + 12x - 192 = 0$
$\Rightarrow x(x - 16) + 12(x - 16) = 0$
$\Rightarrow (x - 16)(x + 12) = 0$
Either x - 16 = 0, then x = 16
Or x + 12 = 0, then x = -12
If x = 16, then
First number = 16 and second number = 16 - 4 = 12
If x = -12, then
First number = -12 and second number = -12 - 4 = -16
Hence numbers are 16, 12 or -12, -16
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