Two parallel plate condensers of capacity of $20 \mu F$ and $30 \mu F$ are charged to the potentials of $30V$ and $20V$ respectively. If likely charged plates are connected together then the common potential difference will be :-......$V$
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Common potential
$\mathrm{V}=\frac{\mathrm{C}_{1} \mathrm{V}_{1}+\mathrm{C}_{2} \mathrm{V}_{2}}{\mathrm{C}_{1}+\mathrm{C}_{2}}=\frac{600+600}{20+30}=24 \mathrm{\,V}$
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