Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is $2 \times {10^5}\,V/m$. When the space is filled with dielectric, the electric field becomes $1 \times {10^5}\,V/m$. The dielectric constant of the dielectric material
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(c) $K = \frac{{{E_{{\rm{without \,dielectric }}}}}}{{{E_{{\rm{with\, dielectric}}}}}} = \frac{{2 \times {{10}^5}}}{{1 \times {{10}^5}}} = 2$
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