MCQ
Two particles in same vertical plane are thrown to strike at same time. One from ground and other from height $h$ vertically above it. Ground particle is thrown obliquly and it achives a maximum height $H$. The second particle is thrown horizontally with same speed. What can be maximum $h$ so that two particles strike in air.
  • A
    $H$
  • B
    $2H$
  • C
    $3H$
  • $4H$

Answer

Correct option: D.
$4H$
d
$\frac{\mathrm{h}}{\mathrm{u} \sin \theta} \leq \frac{2 \mathrm{u} \sin \theta}{\mathrm{g}} \Rightarrow \mathrm{h} \leq \frac{2 \mathrm{u}^{2} \sin ^{2} \theta}{\mathrm{g}}=4 \mathrm{H}$

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