c
$\mathrm{r}=\frac{\sqrt{2 \mathrm{mE}_{\mathrm{k}}}}{\mathrm{qB}}$
$\mathrm{r} \propto \sqrt{\mathrm{m}} \quad\left(\mathrm{q}, \mathrm{B}, \mathrm{E}_{\mathrm{k}} \rightarrow \text { same }\right)$
or $m$ $ \propto $ $r^{2}$
$\frac{m_{1}}{m_{2}}=\left(\frac{r_{1}}{r_{2}}\right)^{2}$