Two pendulum have time periods $T$ and $5T/4$. They start $SHM$ at the same time from the mean position. After how many oscillations of the smaller pendulum they will be again in the same phase
A$5$
B$4$
C$11$
D$9$
Medium
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A$5$
a $\mathrm{n}_{1} \mathrm{T}_{1}=(\mathrm{n}+1) \mathrm{T}_{2}$
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