The period of oscillation $=0.05\,s$
The velocity of the wave $=300\,m / s$
To find:- The phase difference between the oscillation of two points.
Solution:- We know that,
Path difference $=\frac{2 \pi}{\lambda} \times$ path difference
Path difference between two points,
$\Delta x =15-10=5\,m$
Time period, $T =0.5^{ s }$
$\Rightarrow$ frequency $v =\frac{1}{ T }=\frac{1}{0.05}=20\,Hz$
Velocity $v =300\,m / s$
$\therefore$ Wavelenght $\lambda=\frac{ v }{ n }=\frac{300}{20}=15\,m$
Hence, phase difference
$\Delta \phi=\frac{2 \pi}{\lambda} \times x =\frac{2 \pi}{15} \times 5=\frac{2 \pi}{3}$
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