Two points on a travelling wave having frequency $500\, Hz$ and velocity $300\, m/s$ are $60^o$ out of phase, then the minimum distance between the two points is ..... $m$
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Wavelength of the wave is$:$
$\lambda=\frac{v}{f}=\frac{300}{500}=0.6 \mathrm{m}$
$360^{\circ}$ phase difference corresponds to a distance of $1$ wavelength or
$360^{\circ}$ phase difference corresponds to a distance of $0.6 \mathrm{m}$
$60^{\circ}$ phase difference corresponds to a distance of $0.6 / 6=0.1 \mathrm{m}$
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