MCQ
Two points separated by a distance of $0.1\; mm$ can just be resolved in a microscope when a light of wavelength $6000 \;\mathring A$ is used. If the light of wavelength $4800 \;\mathring A$ is used this limit of resolution becomes
  • $0.08$
  • B
    $0.10$
  • C
    $0.12$
  • D
    $0.06 $

Answer

Correct option: A.
$0.08$
a
$ (R.L.) \propto \lambda $

==> $\frac{{{{(R.L.)}_1}}}{{{{(R.L.)}_2}}} = \frac{{{\lambda _1}}}{{{\lambda _2}}}$

==> $\frac{{0.1}}{{{{(R.L.)}_2}}} = \frac{{6000}}{{4800}}$

==> ${(R.L.)_2} = 0.08\,mm$.

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