Question
Two possible stereo-structures of $CH_3CHOHCOOH,$ which are optically active, are called

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$(A)$ Upon heating, $H _3 PO _3$ undergoes disproportionation reaction to produce $H _3 PO _4$ and $PH _3$.
$(B)$ While $H _3 PO _3$ can act as reducing agent, $H _3 PO _4$ cannot.
$(C)$ $H _3 PO _3$ is a monobasic acid.
$(D)$ The $H$ atom of $P - H$ bond in $H _3 PO _3$ is not ionizable in water.
Reason : Iodide stabilizes higher oxidation state