Question
Two resistances when connected in parallel give resultant value of 2 ohm; when connected in series the value becomes 9 ohm. Calculate the value of each resistance.

Answer

Two resistance when connected in series, resultant value is 9 ohms.

Two resistance when connected in parallel, resultant values is 2 ohms.

Let the two resistance be R1 and R2

If connected in series, then

 9 = R1 + R2

R1 = 9 - R2

If connected in parallel, then

$\frac{1}{2}=\frac{1}{\text{R}_1}+\frac{1}{\text{R}_2}$

From aboves equations we get that

$\frac{1}{2}=\frac{(\text{R}_1+\text{R}_2)}{\text{R}_1\text{R}_2}$

$\frac{1}{2}=\frac{9}{(9-\text{R}_2)\text{R}_2}$

$9\text{R}_2-\text{R}_2{^2}=18$

$\text{R}_2{^2}-9\text{R}_2+18=0$

$(\text{R}_2-6)(\text{R}_2-3)=0$

$\text{R}_2=6,3$

So if R2 6 ohms, then R1 = 9 - 6 = 3 ohms.

If R2 = 3 ohms, then R1 = 9 - 3 = 6 ohms.

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