Two resistors 400, Omega and 800, Omega are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10,

Q: Two resistors $400\, \Omega$ and $800\, \Omega$ are connected in series across a $6 V$ battery. The potential difference measured by a voltmeter of $10\, k \Omega$ across $400\, \Omega$ resistor is close to$....V$

b So the potential difference in voltmeter across the points $A$ and $B$ is $\frac{6}{1185} \times 385=1.949 V$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two resistors $400\, \Omega$ and $800\, \Omega$ are connected in series across a $6 V$ battery. The potential difference measured by a voltmeter of $10\, k \Omega$ across $400\, \Omega$ resistor is close to$....V$

A$2$
B$1.95$
C$2.05$
D$1.8$

JEE MAIN 2020, Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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