Two resistors of resistance, $100\,\Omega$ and $200\,\Omega$ are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in $100\,\Omega$ to that in $200\,\Omega$ in a given time is:
A$2: 1$
B$1: 4$
C$4: 1$
D$1: 2$
NEET 2022, Medium
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A$2: 1$
a As both resistors are in parallel combination so potential drop $( V )$ across both are same.
$P =\frac{ V ^{2}}{ R } \Rightarrow P \propto \frac{1}{ R }$
$\frac{ P _{1}}{ P _{2}}=\frac{ R _{2}}{ R _{1}}=\frac{200}{100}=\frac{2}{1}$
$=2: 1$
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