When connected across the terminals of a cell, a voltmeter measures $5\,V$ and a connected ammeter measures $10\, A$ of current. A resistance of $2\, ohms$ is connected across the terminals of the cell. The current flowing through this resistance will be ............ $A$
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(b) Emf $E = 5\,V$ , Internal resistance $r = \frac{5}{{10}} = 0.5\,\Omega $
Current through the resistance $i = \frac{5}{{(2 + 0.5)}} = 2\,A$
Current through the resistance $i = \frac{5}{{(2 + 0.5)}} = 2\,A$
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