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Two rods $A$ and $B$ of same cross-sectional are $A$ and length $l$ connected in series between a source $(T_1 = 100^o C)$ and a sink $(T_2 = 0^o C)$ as shown in figure. The rod is laterally insulated  If $G_A$ and $G_B$ are the temperature gradients across the rod $A$ and $B$, then 
  • A$\frac{{{G_A}}}{{{G_B}}} = \frac{3}{1}$
  • B$\frac{{{G_A}}}{{{G_B}}} = \frac{1}{3}$
  • C$\frac{{{G_A}}}{{{G_B}}} = \frac{3}{4}$
  • D$\frac{{{G_A}}}{{{G_B}}} = \frac{4}{3}$
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