Two rods of same length and material transfer a given amount of heat in $12$ seconds, when they are joined end to end. But when they are joined lengthwise, then they will transfer same heat in same conditions in ....... $\sec$
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(d) Let the heat transferred be $ Q$ .
When rods are joined end to end. Heat transferred by each rod $ = Q = \frac{{K2A\Delta \theta }}{l} \times 12$ ….$.(i)$
When rods are joined lengthwise, $Q = \frac{{KA\Delta \theta }}{{2l}}t$ ….$(ii)$
From equation $(i)$ and $(ii)$ we get $t = 48\;s$
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