MCQ
Two salts $A _{2} X$ and $MX$ have the same value of solubility product of $4.0 \times 10^{-12}$. The ratio of their molar solubilities i.e. $\frac{S\left(A_{2} X\right)}{S(M X)}=...........$

(Round off to the Nearest Integer).

  • A
    $40$
  • $50$
  • C
    $45$
  • D
    $55$

Answer

Correct option: B.
$50$
b
For $A _{2} X$

$A _{2} X \rightarrow 2 A ^{+}+ X ^{2-}$

$2 S _{1} \quad S _{1}$

$K _{ sp }=4 S _{1}^{3}=4 \times 10^{-12}$

$S _{1}=10^{-4}$

for $MX$

$MX \rightarrow M ^{+}+ X ^{-}$

$\begin{array}{ll} S _{2}  S _{2}\end{array}$

$K _{ sp }= S _{2}^{2}=4 \times 10^{-12}$

$S _{2}=2 \times 10^{-6}$

so $\frac{ S _{ A _{2} x }}{ S _{ MX }}=\frac{10^{-4}}{2 \times 10^{-6}}=50$

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