- A$11$
- ✓$10$
- C$21$
- D$20$
Only when number of completed oscillation differs by an integer, the two pendulum will again begin to swing together.
Let longer length pendulum complete $n$ oscillation and shorter length pendulum complete $(n+1)$ oscillation, for the unision swinging, then $(n + 1){T_1} = n{T_2}$
$(n + 1) \times 2\pi \sqrt {\frac{{100}}{g}} = n \times 2\pi \sqrt {\frac{{121}}{g}} $$ \Rightarrow n = 10$
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$(A)$For a given material of the capillary tube, $\mathrm{h}$ decreases with increase in $\mathrm{r}$.
$(B)$ For a given material of the capillary tube, $\mathrm{h}$ is independent of $\sigma$
$(C)$ If this experiment is performed in a lift going up with a constant acceleration, then $\mathrm{h}$ decreases
$(D)$ $\mathrm{h}$ is proportional to contact angel $\theta$