- AMass
- BRadius
- CDensity
- ✓All of these
For rolling down an inclined plane,
$a_{c m}=\frac{g \sin \theta}{1+\frac{1}{m R^2}}$
For 5 phere of mass $m$ and radius $R, 1=\frac{2}{5} m R^2$
So, $\quad a_{c u}=\frac{g \sin 0}{1-\frac{2}{5}\left({m R^2}^2\right)}=\frac{5}{7} g \sin 0$
As acceleration of centre of mass of rolling body only depends upon angle of inclination,
So, time taken to come down, $t =\sqrt{\frac{2 L}{a_{c h}}}$
$\left(\because L=\frac{1}{2} a_{c n} t^2\right)$
$t=\sqrt{\frac{2 L \times 7}{5 g \sin \theta}}=\sqrt{\frac{14 L}{5 g \sin \theta}}$, where $L=$ length of inclined plane.
Here, $t$ is independent of mass, radius and density of spheres. Option (d) is correct.
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($1$) The $8^{\text {mh }}$ bright fringe above the point $O$ oscillates with time between two extreme positions. The separation between these two extreme positions, in micrometer $(\mu m )$, is. . . . .
($2$) The maximum speed in $\mu m / s$ at which the $8^{\text {th }}$ bright fringe will move is. . . . .
Give the answer or quetion ($1$) and ($2$)


$\vec{r}(t)=\alpha t^3 \hat{i}+\beta t^2 \hat{j}$
where $\alpha=10 / 3 \mathrm{~m} \mathrm{~s}^{-3}, \beta=5 \mathrm{~m} \mathrm{~s}^{-2}$ and $m=0.1 \mathrm{~kg}$. At $t=1 \mathrm{~s}$, which of the following statement($s$) is(are) true about the particle?
($A$) The velocity $\vec{v}$ is given by $\vec{v}=(10 \hat{i}+10 \hat{j}) \mathrm{ms}^{-1}$
($B$) The angular momentum $\vec{L}$ with respect to the origin is given by $\vec{L}=-15 / 3) \hat{k} \mathrm{~N} \mathrm{~m} \mathrm{~s}$
($C$) The force $\vec{F}$ is given by $\vec{F}=(\hat{i}+2 \hat{j}) \mathrm{N}$
($D$) The torque $\vec{\tau}$ with respect to the origin is given by $\vec{\tau}=-(20 / 3) \hat{k} \mathrm{~N} \mathrm{~m}$
