MCQ
Two solids spheres of iron have radii in the ratio $1 : 2$. Their moments of inertia will be in the ratio
  • A
    $1:4$
  • B
    $1:8$
  • C
    $1:16$
  • $1:32$

Answer

Correct option: D.
$1:32$
d
Moment of inertia of a solid sphere $=\frac{2}{5} \mathrm{mr}^{2}$

$\mathrm{m}=\frac{4}{3} \pi \mathrm{r}^{3} \mathrm{d},$ i.e.,$\mathrm{I} \alpha \mathrm{r}^{5}$

Hence, required ratio $=1: 2^{5}$

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