MCQ
Two solids spheres of iron have radii in the ratio $1 : 2$. Their moments of inertia will be in the ratio
- A$1:4$
- B$1:8$
- C$1:16$
- ✓$1:32$
$\mathrm{m}=\frac{4}{3} \pi \mathrm{r}^{3} \mathrm{d},$ i.e.,$\mathrm{I} \alpha \mathrm{r}^{5}$
Hence, required ratio $=1: 2^{5}$
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