MCQ
Two sound sources when sounded simultaneously produce four beats in $0.25$ second. the difference in their frequencies must be
  • A
    $4$
  • B
    $8$
  • $16$
  • D
    $1$

Answer

Correct option: C.
$16$
c
(c) No. of beats = frequency difference = $\frac{4}{{0.25}} = 16$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is $10.2 \ eV$. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of $15 \ eV$. What will be observed by the detector
A coin placed on a rotating table just slips when it is placed at a distance of $1\,cm$ from the center. If the angular velocity of the table in halved, it will just slip when placed at a distance of from the centre $............\,cm$
The value of g on the earth's surface is $980\,cm/{\sec ^2}$. Its value at a height of $64 \,km$ from the earth's surface is ........ $cm/{\sec ^2}$

(Radius of the earth $R = 6400$ kilometers) 

Two vectors $\overrightarrow A $and $\overrightarrow B $lie in a plane, another vector $\overrightarrow C $lies outside this plane, then the resultant of these three vectors i.e.,$\overrightarrow A + \overrightarrow B + \overrightarrow C $
A car travels a distance $S$ on a straight road in two hours and then returns to the starting point in the next three hours. Its average velocity is
A uniform rectangular thin sheet $ABCD$ of mass $M$ has length $a$ and breadth $b$, as shown in the figure. If the shaded portion $HBGO$ is cut off, the coordinates of the centre of mass of the remaining portion will be
A spherical planet has a mass $M$ and diameter $D$ . A particle of mass $m$ falling freely near the surface of this planet will experience an acceleration due to gravity , equal to  
Modern vacuum pumps can evacuate a vessel down to a pressure of $4.0 \times {10^{ - 15}}\, atm$ at room temperature $(300\, K)$. Taking $R = 8.0\, JK^{-1}\, mole^{-1}$ , $1\, atm = 10^5\, Pa$ and $N_ {Avogadro} = 6 \times 10^{23}\, mole^{-1}$ , the mean distance between molecules of gas in an evacuated vessel will be of the order of
Gravitational force between two identical uniform solid gold spheres of radius r reach in contact is proportional to
The temperature of a piece of iron is ${27^o}C$ and it is radiating energy at the rate of $Q\;kW{m^{ - 2}}$. If its temperature is raised to ${151^o}C$, the rate of radiation of energy will become approximately ....... $Q\,kW\,{m^{ - 2}}$