Two straight long conductors $AOB$ and $COD$ are perpendicular to each other and carry currents ${i_1}$ and ${i_2}$. The magnitude of the magnetic induction at a point $ P$ at a distance a from the point $O$ in a direction perpendicular to the plane $ACBD$ is
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$STATEMENT-1$ A vertical iron rod has a coil of wire wound over it at the bottom end. An alternating current flows in the coil. The rod goes through a conducting ring as shown in the figure. The ring can float at a certain height above the coil. Because
$STATEMENT- 2$ In the above situation, a current is induced in the ring which interacts with the horizontal component of the magnetic field to produce an average force in the upward direction.
The relation between voltage sensitivity (${\sigma _V}$) and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)
Due to the flow of current in a circular loop of radius $R$, the magnetic induction produced at the centre of the loop is $B$. The magnetic moment of the loop is $({\mu _0} = {\rm{permeability}}\,{\rm{constant)}}$
A galvanometer gives full scale reading of $50\ mA$ , when a $p.d.$ , across its terminals is $0.15\ V$ . It can be used as an ammeter of range $0 - 100\ A$ by connecting a shunt resistance of
In the experiment to determine the galvanometer resistance by half-deflection method, the plot of $\frac{1}{\theta}$ vs the resistance $(R)$ of the resistance box is shown in the figure. The figure of merit of the galvanometer is .............. $\times 10^{-1} \mathrm{~A} /$ division. [The source has emf 2V]
A straight wire carrying a current ${i_1}\,amp$ runs along the axis of a circular current ${i_2}\,amp$. Then the force of interaction between the two current carrying conductors is
A galvanometer having a coil resistance of $60\,\Omega $ shows full scale deflection when a current of $1.0\, amp$ passes through it. It can be converted into an ammeter to read currents upto $5.0\, amp$ by