The relation between voltage sensitivity (${\sigma _V}$) and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)
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(a) ${\sigma _i} = \frac{\theta }{i} = \frac{\theta }{{iG}} \cdot G = {\sigma _{_V}}G$ $==>$ $\frac{{{\sigma _i}}}{G} = {\sigma _V}$
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