MCQ
Two supplementary angles are in the ratio $4 : 5.$ The angles are
- A$90^\circ , 90^\circ$
- ✓$80^\circ , 100^\circ$
- C$30^\circ , 150^\circ$
- D$45^\circ , 45^\circ$
Let the angles be $4x$ and $5x$ Angles are supplementary
$\therefore 4x + 5x = 180^\circ $
$\Rightarrow 9x = 180^\circ $
$\Rightarrow x = 20^\circ $
So the angles are
$4 \times 20^\circ = 80^\circ $
$5 \times 20^\circ = 100^\circ $
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