Two trains move towards each other with the same speed. The speed of sound is $340 \;m / s$. If the height of the tone of the whistle of one of them heard on the other changes $9 / 8$ times, then the speed of each train should be ........... $m/sec$
AIPMT 1991, Medium
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Here, $v^{\prime}=\frac{9}{8} v$

Source and observer are moving in opposite direction, therefore, apparent frequency $v^{\prime}=v \times \frac{(v+u)}{(v-u)}$

$\frac{9}{8} v=v \times \frac{340+u}{340-u}$

$\Rightarrow 9 \times 340-9 u=8 \times 340+8 u$

$\Rightarrow 17 u=340 \times 1 \Rightarrow u=\frac{340}{17}=20 m / sec$

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