Two travelling waves produces a standing wave represented by equation,
${y}=1.0\, {mm} \cos \left(1.57 \,{cm}^{-1}\right) {x} \sin \left(78.5\, {s}^{-1}\right) {t}$
The node closest to the origin in the region ${x}>0$ will be at ${x}=\ldots \ldots \ldots\, {cm}$
JEE MAIN 2021, Medium
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For node
$\cos \left(1.57 {cm}^{-1}\right) {x}=0$
$\left(1.57 {cm}^{-1}\right) {x}=\frac{\pi}{2}$
${x}=\frac{\pi}{2(1.57)} {cm}=1\, {cm}$
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