Two vessels of different materials are similar in size in every respect. The same quantity of ice filled in them gets melted in $20$ minutes and $40$ minutes respectively. The ratio of thermal conductivities of the materials is 
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(d) $\frac{Q}{t} = \frac{{KA({\theta _1} - {\theta _2})}}{l}$ ==> $\frac{{mL}}{t} = \frac{{KA({\theta _1} - {\theta _2})}}{l}$

==> $K \propto \frac{1}{t}$ ( $\because$ remaining quantities are same)

==> $\frac{{{K_1}}}{{{K_2}}} = \frac{{{t_2}}}{{{t_1}}}$$ = \frac{{40}}{{20}} = \frac{2}{1}$.

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