Two waves are given by ${y_1} = a\sin (\omega t - kx)$ and ${y_2} = a\cos (\omega \,t - kx)$ The phase difference between the two waves is
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(d) ${y_1} = a\sin (\omega t - kx)$
and ${y_2} = a\cos (\omega t - kx) = a\sin \,\left( {\omega \,t - kx + \frac{\pi }{2}} \right)$
Hence phase difference between these two is $\frac{\pi }{2}.$
and ${y_2} = a\cos (\omega t - kx) = a\sin \,\left( {\omega \,t - kx + \frac{\pi }{2}} \right)$
Hence phase difference between these two is $\frac{\pi }{2}.$
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