${x_1} = a\sin (\omega \,t + {\phi _1})$, ${x_2} = a\sin \,(\omega \,t + {\phi _2})$
If in the resultant wave the frequency and amplitude remain equal to those of superimposing waves. Then phase difference between them is
- A$\frac{\pi }{6}$
- ✓$\frac{{2\pi }}{3}$
- C$\frac{\pi }{4}$
- D$\frac{\pi }{3}$