Since wires have same material so $r$ and $d$ is same for both.

Also they have same mass $ \Rightarrow $ $Al$ $=$ constant $ \Rightarrow $ $l \propto \frac{1}{A}$

$ \Rightarrow $ $\frac{{{R_1}}}{{{R_2}}} = \frac{{{l_1}}}{{{l_2}}} \times \frac{{{A_2}}}{{{A_1}}} = {\left( {\frac{{{A_2}}}{{{A_1}}}} \right)^2} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^4}$

$ \Rightarrow $ $\frac{{34}}{{{R_2}}} = {\left( {\frac{r}{{2r}}} \right)^4}$ $ \Rightarrow $ ${R_2} = 544\,\Omega $