Five resistances are connected as shown in the figure. The effective resistance between the points $A$ and $B$ is
A$\frac{{10}}{3}\,\Omega $
B$\frac{{20}}{3}\,\Omega $
C$15\,\Omega $
D$6\,\Omega $
Medium
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A$\frac{{10}}{3}\,\Omega $
a The given circuit is a balanced Wheatstone bridge type, hence it can be simplified as follows
$R_{AB}=\frac {10}{3}\,\Omega $
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