Two wires of equal lengths are made of the same material. Wire $A$ has a diameter that is twice as that of wire $B$. If identical weights are suspended from the ends of these wires, the increase in length is
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(d) $l = \frac{{FL}}{{AY}}$ $⇒$ $l \propto \frac{1}{{{r^2}}}$ $(F,L$ and $Y$ are same$)$
$\frac{{{l_A}}}{{{l_B}}} = {\left( {\frac{{{r_B}}}{{{r_A}}}} \right)^2}$
$\frac{{{l_A}}}{{{l_B}}} = {\left( {\frac{{{r_B}}}{{2{r_B}}}} \right)^2} = \frac{1}{4}$
$⇒$ ${l_B} = 4{l_A}$
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