Ultrasonic signal sent from $SONAR$ returns to it after reflection from a rock after a lapse of $1 \,sec.$ If the velocity of ultrasound in water is $1600 ms^{-1}$, the depth of the rock in water is ..... $m$
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(d) If $d$ is the distance of rock from $SONAR$ then
$2d = vt$==> $d = \frac{{v \times t}}{2} = \frac{{1600 \times 1}}{2} = 800m$
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